Tipragot
628be439b8
Cela permet de ne pas avoir de problèmes de compatibilité car python est dans le git.
82 lines
2.5 KiB
Python
82 lines
2.5 KiB
Python
# Licensed under the LGPL: https://www.gnu.org/licenses/old-licenses/lgpl-2.1.en.html
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# For details: https://github.com/pylint-dev/astroid/blob/main/LICENSE
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# Copyright (c) https://github.com/pylint-dev/astroid/blob/main/CONTRIBUTORS.txt
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"""Different utilities for the numpy brains."""
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from __future__ import annotations
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from astroid.builder import extract_node
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from astroid.context import InferenceContext
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from astroid.nodes.node_classes import Attribute, Import, Name
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# Class subscript is available in numpy starting with version 1.20.0
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NUMPY_VERSION_TYPE_HINTS_SUPPORT = ("1", "20", "0")
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def numpy_supports_type_hints() -> bool:
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"""Returns True if numpy supports type hints."""
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np_ver = _get_numpy_version()
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return np_ver and np_ver > NUMPY_VERSION_TYPE_HINTS_SUPPORT
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def _get_numpy_version() -> tuple[str, str, str]:
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"""
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Return the numpy version number if numpy can be imported.
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Otherwise returns ('0', '0', '0')
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"""
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try:
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import numpy # pylint: disable=import-outside-toplevel
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return tuple(numpy.version.version.split("."))
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except (ImportError, AttributeError):
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return ("0", "0", "0")
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def infer_numpy_member(src, node, context: InferenceContext | None = None):
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node = extract_node(src)
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return node.infer(context=context)
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def _is_a_numpy_module(node: Name) -> bool:
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"""
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Returns True if the node is a representation of a numpy module.
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For example in :
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import numpy as np
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x = np.linspace(1, 2)
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The node <Name.np> is a representation of the numpy module.
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:param node: node to test
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:return: True if the node is a representation of the numpy module.
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"""
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module_nickname = node.name
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potential_import_target = [
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x for x in node.lookup(module_nickname)[1] if isinstance(x, Import)
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]
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return any(
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("numpy", module_nickname) in target.names or ("numpy", None) in target.names
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for target in potential_import_target
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)
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def name_looks_like_numpy_member(member_name: str, node: Name) -> bool:
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"""
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Returns True if the Name is a member of numpy whose
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name is member_name.
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"""
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return node.name == member_name and node.root().name.startswith("numpy")
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def attribute_looks_like_numpy_member(member_name: str, node: Attribute) -> bool:
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"""
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Returns True if the Attribute is a member of numpy whose
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name is member_name.
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"""
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return (
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node.attrname == member_name
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and isinstance(node.expr, Name)
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and _is_a_numpy_module(node.expr)
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)
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